C++多線程

Question

在一個類中，當我嘗試創建一個線程像這樣的方法：

void *RippleBrush::paintRippleOnce(void){ 
    while(1){ 
     for (int j = 0; j < height; j ++) { 
      for(int i = 0; i < width; i ++){ 
       int point = j * height + i; 
       data[point].a += ripple->rippleNow[point]; 
       ripple->CaculateNextRipple(); 
      } 
     } 
    } 
} 

void RippleBrush::paintRipple(){ 
    pthread_t ctrl_thread; 
     if(pthread_create(&ctrl_thread, NULL, RippleBrush::paintRippleOnce, NULL) != 0){ 
      perror("pthread_create"); 
      exit(1); 
     } 
} 

它顯示錯誤：調用「在pthread_create」沒有匹配的功能。

如何在同一個類中的另一個方法創建一個方法的線程？

Answer 1

#include <pthread.h> 

int pthread_create(pthread_t *thread, const pthread_attr_t *attr, 
        void *(*start_routine) (void *), void *arg); 

編譯和鏈接與-pthread。

Answer 2

我看你最好讓你的真正的工人功能爲靜態：

void *RippleBrush::paintRippleOnce(void){ 
    while(1){ 
     for (int j = 0; j < height; j ++) { 
      for(int i = 0; i < width; i ++){ 
       int point = j * height + i; 
       data[point].a += ripple->rippleNow[point]; 
       ripple->CaculateNextRipple(); 
      } 
     } 
    } 
} 

void RippleBrush::paintRipple(){ 
    pthread_t ctrl_thread; 
     if(pthread_create(&ctrl_thread,NULL, RippleBrush::paintRippleOnceWrapper,this)!=0){ 
      perror("pthread_create"); 
      exit(1); 
     } 
} 

static void* RippleBrush::paintRippleOnceWrapper(void *args) { 
    RippleBrush* brush= (RippleBrush*)args; // or dynamic_cast as you like 
    brush->paintRippleOnce(); 
}