2017-10-21 138 views
-3

我是新來的Android,我試圖做一個按鈕打開2個活動,但沒有爲我工作。 爲前: 上Mainacitivity,有btn_mathematicsbtn_physics打開相同的活性(Main2acitivity),並找到btn_semester1btn_semester2,每個按鈕將打開其他2個活動學期模塊。按鈕,如果條件

如果Mainacitivity用戶點擊上: btn_mathematics --->btn_semester1 --->將有ModulesMAT 如果放在btn_semester1同一按鈕點擊: btn_physics --->btn_semester1 --->將有ModulesPHY

MainActivity XML:

<Button 
    android:id="@+id/btn_mathematics" 
    android:onClick="btn_mathematics" 
    android:text="@string/btn_mathematics/> 

<Button 
    android:id="@+id/btn_physics" 
    android:onClick="btn_physics" 
    android:text="@string/btn_physics"/> 

Main2Activity XML:

<Button 
    android:id="@+id/btn_semester1" 
    android:onClick="btn_semester1" 
    android:text="@string/btn_semester1"/> 

<Button 
    android:id="@+id/btn_semester2" 
    android:onClick="btn_s2" 
    android:text="@string/btn_semester2"/> 

我想,沒有必要添加XML爲ModulesMAT和ModulesPHY,它很類似於其他人。

現在的Java代碼:

MainActivity.java:

@Override 
protected void onCreate(Bundle savedInstanceState) { 
     super.onCreate(savedInstanceState); 
     setContentView(R.layout.activity_main); 
    } 

    public void btn_mathematics (View v) { 
     Intent intent = new Intent(MainActivity.this, Main2Activity.class); 
     startActivity(intent); 
    } 

    `public void btn_physics (View v) { 
     Intent intent = new Intent(MainActivity.this, Main2Activity.class); 
     startActivity(intent); 
    } 


} 

Main2Activity.java:

@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main2); 
} 



public void btn_semester1 (View v) 
{ 
    Intent i = getIntent(); 
    String id = i.getStringExtra("id"); 
    if(id == "btn_mathematics") 
    { 
     i = new Intent(this, ModulesMAT.class); 
     startActivity(i); 
    } 
    else if (id == "btn_physics") 
    { 
     i = new Intent(this, ModulesPHY.class); 
     startActivity(i); 
    } 

} 


public void btn_semester2 (View v) 
{ 
    Intent i = getIntent(); 
    String id = i.getStringExtra("id"); 
    if(id == "btn_mathematics") 
    { 
     i = new Intent(this, ModulesMAT2.class); 
     startActivity(i); 
    } 
    else if (id == "btn_physics") 
    { 
     i = new Intent(this, ModulesPHY2.class); 
     startActivity(i); 
    } 

} 
+0

你可以通過'Intent'傳遞活動之間的數據。這裏是一個例子https://stackoverflow.com/a/2091482/1552587 – Titus

+0

謝謝你的評論,我可以在我的代碼上有一個例子嗎? – itray

回答

1

在MainActivity你可以通過ID識別成Main2Activity。
MainActivity

public void btn_mathematics (View v) { 
     Intent intent = new Intent(MainActivity.this, Main2Activity.class); 
     Bundle bundle = new Bundle(); 
     bundle.putString("id","Math"); 
     intent.putExtra(bundle); 
     startActivity(intent); 
    } 

public void btn_physics (View v) { 
    Intent intent = new Intent(MainActivity.this, Main2Activity.class); 
    Bundle bundle = new Bundle(); 
    bundle.putString("id","Physics"); 
    intent.putExtra(bundle); 
    startActivity(intent); 
} 

Main2Activity

String id; 
@Override 
protected void onCreate(Bundle savedInstanceState) { 
    super.onCreate(savedInstanceState); 
    setContentView(R.layout.activity_main2); 

    Bundle bundle = getIntent().getExtras(); 
    id= bundle.getString("id"); 
} 

public void btn_semester1 (View v) 
{ 
    if(id == "Math") 
    { 
     i = new Intent(this, ModulesMAT2.class); 
     startActivity(i); 
    } 
    else if (id == "Physics") 
    { 
     i = new Intent(this, ModulesPHY2.class); 
     startActivity(i); 
    } 

} 


public void btn_semester2 (View v) 
{ 
    if(id == "Math") 
    { 
     i = new Intent(this, ModulesMAT2.class); 
     startActivity(i); 
    } 
    else if (id == "Physics") 
    { 
     i = new Intent(this, ModulesPHY2.class); 
     startActivity(i); 
    } 

} 
+0

你應該使用'... equals(...)'來比較'String's而不是'==' – Titus

+0

你幫助我的男人,非常感謝你, 只是我的第二個活動的一個小問題,與你代碼: 'if(id ==「Math」) { i = new Intent(this,ModulesMAT2.class); startActivity(i); } else if(id ==「Physics」) { i = new Intent(this,ModulesPHY2.class); startActivity(i); } } 我有 (無法解析symbole'i') – itray

+0

只需在每個i之前添加Intent。像:Intent i = new Intent(this,ModulesMat2.class); –